300(t)=-16t^2+150t

Solution for 300(t)=-16t^2+150t equation:

300(t)=-16t^2+150t

We move all terms to the left:

300(t)-(-16t^2+150t)=0

We get rid of parentheses

16t^2-150t+300t=0

We add all the numbers together, and all the variables

16t^2+150t=0

a = 16; b = 150; c = 0;
Δ = b2-4ac
Δ = 1502-4·16·0
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-150}{2*16}=\frac{-300}{32}
=-9+3/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+150}{2*16}=\frac{0}{32}
=0
$